unfinished+math+forum

A Dicey Situation by Ashley

Player A's numbers are 012, and Player B's numbers are 345.So we have to figure out who will win. The way you have to do it is subtract 6-5 6-6 6-4 6-3 6-2 6-1 6-0 and then do it with the 5s,4s,3s,2s and 1s. Then, you have to see if the number is player As number or player Bs number. Finally, you Count the As and Bs and if the As have more they win and if the Bs have more they win. 1 1 0 (A) 3 1 2 (A) 5 1 4 (B) 1 2 1 (A) 3 2 1 (A) 5 2 3 (B) 1 3 2 (A) 3 3 0 (A) 5 3 2 (A) 1 4 3 (B) 3 4 1 (A) 5 4 1 (A) 1 5 4 (B) 3 5 2 (A) 5 5 0 (A) 1 6 5 (B ) 3 6 3 (B) 5 6 1 (A) 2 1 1 (A) 4 1 3 (B) 6 1 5 (B) 2 2 0 (A) 4 2 2 (A) 6 2 4 (B) 2 3 1 (A) 4 3 1 (A) 6 3 3 (B) 2 4 2 (A) 4 4 0 (A) 6 4 2 (A) 2 5 3 (B) 4 5 1 (A) 6 5 1 (A) 2 6 4 (B) 4 6 2 (A) 6 6 0 (A)

Solution: A Dicey Situation By Yusufhan Ergul The answer is Player A because there are 15 ways to win and 6 ways for Player B. Here is how I got the answer. When the larger number is 6 they both have 3 ways to win. When the larger number is 5